January 20th, 2025

Where Do Those Undergraduate Divisibility Problems Come From?

The blog post by Chris Grossack examines undergraduate divisibility problems in polynomials, emphasizing combinatorial counting, the Pólya-Redfield theorem, and providing examples like bracelets and tic-tac-toe boards.

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Where Do Those Undergraduate Divisibility Problems Come From?

The blog post by Chris Grossack explores the origins of undergraduate divisibility problems, particularly those involving polynomials that yield multiples of a specific integer. Grossack discusses how these problems often arise in introductory proof or discrete math classes, using the example of the polynomial \(P(n) = n^6 + n^3 + 2n^2 + 2n\), which is always divisible by 6. The author emphasizes the importance of combinatorial counting in ensuring that polynomial outputs are integers, suggesting that counting orbits of group actions can lead to such divisibility. The Pólya-Redfield counting theorem is introduced as a method to derive polynomials that are guaranteed to be divisible by the order of a group. Grossack provides examples, including counting the number of distinct bracelets and tic-tac-toe boards, to illustrate how these concepts apply in practice. The post concludes with a conjecture regarding the relationship between polynomials that are multiples of a fixed integer and their derivation from combinatorial counting methods.

- The blog discusses the origins of divisibility problems in undergraduate mathematics.

- It highlights the role of combinatorial counting in ensuring polynomial outputs are integers.

- The Pólya-Redfield counting theorem is presented as a method for deriving divisible polynomials.

- Examples include counting distinct bracelets and tic-tac-toe boards.

- A conjecture is proposed about the relationship between certain polynomials and combinatorial counting.

Link Icon 8 comments
By @jmount - 16 days
By @t43562 - 15 days
My daily dose of inferiority: done. :-) Perfect sentences which are complete gobblede-gook to me.
By @agnishom - 15 days
TLDR Summary:

There is a genre of undergraduate polynomial divisibility problems which look like this: Show that f(n) is divisible by some integer k.

These problems often appear to be (elementary) number theory problems. However, often there is a rather elegant proof associated with them which is based on combinatorics.

The crux of this proof is that the polynomial counts the number of equivalence classes of a certain kind.

This is closely related to https://en.wikipedia.org/wiki/Burnside%27s_lemma

The question at the end of the post is whether _all_ such problems must come this way

By @np_tedious - 15 days
Well I was curious, but there's a lot there I didn't understand. Apparently I'm good enough at math to do the proofs, but not to write the exercises.

Exercise left to the reader:

Prove 7*n^3 + n is divisible by 2

By @daef - 15 days
i couldnt come up with a proof for the initial problem (n^6+n^3+2n^2 is a multiple of 6 for every n)

because it's not true (simply insert 1, 2, 4 or 5)

By @nh23423fefe - 14 days
i just computed the solution mod 2 and mod 3 a la chinese remainder theorem

the polynomial is =0 mod2 and =0 mod3 so its =0 mod6

n^6 + n^3 + 2n^2 + 2n (mod 2) = n^6 + n^3 + 0 + 0 = n^3(n^3+1) = 0*1 or 1*0 = 0

because consecutive numbers are even then odd then even ....

for mod3 you can make a table

you could also factor the polynomial and see the solution easily

n(n+1)(n^2-2n+2)(n^2+n+1)

By @dang - 15 days
[stub for offtopicness]